Recent content by Tom4

So ##\Delta U = \Delta KE## Makes sense when you put it like that, thanks.

Solved: ##v^2 = v^2_i + v^2_f## ##v = \sqrt {v^2_i + v^2_f}## Using escape velocity formula ##v = \sqrt \frac {2GM} {R}## for final velocity: ##v = \sqrt {v^2_i + \frac {2GM} {R}}## v = 6180 meters per second

Well the potential energy would be 0 since I assume they mean the radius is infinite. But that doesn't make sense because it eventually impacts mars at a different speed. Right?

Since the radius is "very far", I cannot find the total mechanical energy by using the gravitational potential energy formula and find the kinetic energy at impact. I can't think of any other way to find final velocity without knowing the radius.