Recent content by tommy-d

the only formula i can get close to for this is ax = T/m- g sin9° i have written this out to be 0/1200-9.81sin(9) = -1.53. this would mean that the speed when the car would be exiting the ramp would be 1.53 m/s but I'm not confident on this answer as it doesn't mention the length of the ramp in...

Hi there currently I am stuck on a question, A car with a mass of 1.2 tonnes, rolls down a hill which is 600m long and is inclined at an angle of 9 degrees to the horizontal. Ignoring the effects of air resistance and friction and assuming the car to start from rest at the top of the hill...