i have worked out angle BCD as being 59 degrees
and worked out the area of triangle BCD as having an area of 6946m^2
just trying to find the side AD is puzzling me
Homework Statement
i need to find angle BDC and side BC when given that
AB = 60m
BAC = 64
AC = 124
BD = 130
CD = 145
and to find the area of the whole plot
Homework Equations
The Attempt at a Solution
i have worked out side BC = 111.59 by using the Co-sine rule
a^2 =...
so therefore the whole right hand side would = ln(xy^3/2) where as the left = log(1/2xy^2)
so where it says 3 ln y it should read 2 ln y
i think i have got this now thanks for your help mark :)
i think there is a typo on the original criteria sheet as it reads 3 ln y when combined this = y^3 so I am thinking that it should be 2 ln y
if so i think i have figured it out if not I am still stumped
it has been a while since i covered structural mechanics but I am sure i can remember that the maximum bending moment occurs at the middle point of the beam and the calc should include (Ra x 1/2l) - (UDL x 1/2b x 1/4l) < try that and let me know how you get on
Ra = reaction
L = length of beam
Homework Statement
log(1/2xy^2) = ln x + 3 ln y - ln 2
Homework Equations
The Attempt at a Solution
i have been trying for hours on with next to no results even just an insight on how to go about it would be helpful