Ah yes I do!
So from 2y2-y-1=0
I get (2y+1)(y-1)=0
I can use this to find my y coordinates and then use the x and y values with my previously found dy/dx to get my slope at both points, correct?
I calculated a slope of 1 at (1,1) and a slope of -1/2 at (1,-1/2).
Thanks a lot!
Homework Statement
a) If 2y2-xy-x2=0 , find dy/dx.
b) What is/are the slope(s) of the tangent(s)at x=1?
Homework Equations
The Attempt at a Solution
Using implicit differentiation:
a) (4y)dy/dx-(x)dy/dx-y(1)-2x=0
(4y)dy/dx-(x)dy/dx=2x+y...