Recent content by trials

alrighhhht worked it out on my own :) I figured, why log to find the rate, 20th root it. 125000/100000=r^20 (20th root) 1.25=r r=1.01 200000=100000(1.01)^t 2=1.01^t log 2/log1.01=t t=62 minutes which is the answer in the back of my textbook. Thanks for setting me on the right path Char.Limit :D

Well i can get this far but i can't get farther sorry. 125000=100000(rate)^20 125000/100000=r^20 log (125000/100000)=20log r I don't know how to go farther, if r had a value and i was solving for time i would have no problem with this.

So would my rate be 2? if so then would this be right 120000=100000(2)^t 1.25=2^t log1.25/log2=t? What confuses me is when it says doubling period, is that time or the rate?

Homework Statement A culture begins with 100,000 bacteria and grows to 125,000 bacteria after 20 min. What is the doubling period to the nearest minute? Homework Equations Current=Original(rate)^time The Attempt at a Solution I can get make the first part out...