Obviously I am approaching this problem from multiple angles. Based on my math and understanding I feel that my answer is correct. I was hoping someone could either correct me or confirm with me. If you are going to correct me please have a valid explanation with a mathematical backup to prove...
For part a you would need to use the potential energy equation involving the spring constant. which is U = 1/2kx^2 set this equal to kinetic energy and solve for velocity. You will also need to know the distance it is stretched. F = kx, F = mg you have these so solve for x. Now to find the...
Yes, I stated that in my response, but since mg is in the Y direction, vertically as you put it and the system is in a 'static equilibrium' there is also a tension T-y in the opposite direction of the force due to gravity. Because of this fact the forces in the y why direction are irrelevant to...
Alright well this is how I am seeing it.
T-2 - T-1 = 0 or T-1 + T-2 + mg = 0
Since there is no forces acting in the Y direction, we are left with the two x components which are supporting the rod, thus the force due to gravity is irrelevant seeing as it is in equilibrium, it cancels out...
Alright well this is how I am seeing it.
T-2 - T-1 = 0 or -T-1 + T-2 = 0 (these are the x components)
Since there is no forces acting in the Y direction, we are left with the two x components which are supporting the rod, thus the force due to gravity is irrelevant seeing as it is in...
Yes, I understand. I have summed up the forces and chosen arbitrary numbers but the tension on the ropes are specific to a certain mass of the rod. I have multiple answers and am unclear on the correct answer and process. And my teacher starts a problem and says you should be able to figure it...
Here is a link with a pic and the question.
http://www.cramster.com/answers-may-10/physics/static-equilibrium-uniform-rod-supported-strings-string-attach_848648.aspx?rec=0
Homework Statement
A uniform rod is supported by two strings. The string on the left hand side is horizontal. The string on the right hand side is at 30 degrees with respect to a straight line going from the end of the bar to the ceiling. If you had a straight line going from the end of the...