Ok, that would be 1500Nm(for the first), I don't know how to figure out the bar moment (as distance is zero and zero* anything is zero), but on the other hand, if it is the sum of the other two moments, then it would be 1950Nm? and 450Nm(for the right-hand weight)
Ah, that was my attempt to figure out the bar weight lol!
Thanks Tim, My level of understanding of this is pretty low though. How would I calculate the bar moment? Would you be kind enough to show me the calcs, so I can take a look please. Sorry to be so dense:blushing:
1. A heavy uniform bar is in equilibrium in the arrrangement shown
(I cannot upload the picture, but the bar is resting on a pivot with two weights at either end. 1.5m to the left of the pivot with 1000N weight at the end. 4.5m to the right of the pivot with a 100N weight at the end)
Question...