Thanks, I managed to get:
V = ∫∫r((R^2-r^2)^.5-a)drdθ with bounds of (R^2-r^2)^.5 to 0 on the dr and bounds of 2*pi to 0 on the dθ. Simplifying this gives me (2R^3-3a*R^2+a^3)*pi/3. Thanks again for your help!
Homework Statement
Find the volume under the sphere x^2+y^2+z^2=r^2 and above the plane z=a, where 0<a<r
Homework Equations
x^2+y^2+z^2=r^2 is the equation of a sphere with radius r centered at the origin
z=a is the equation of a plane with height a parallel to the xy plane
V = ∫∫z...