Recent content by Ushitha Dissanayake

thanks for ur explanation

can you explain why we have to do it this way i still don't understand how this ratio thing works

i tried finding a ratio by dividing (ρ = 1.2 kg/m^3) by (ρ = 1.0 x 10^3 kg/m^3) which gave 1.2*10^-3, then multiplying that with the terminal velocity of it in the air which gave 0.0504/ but the answer is 1.5

"What would be the relation between the terminal velocities in air and water, respectively?" I don't understand what you're implying here

I don't really understand what you said

I'm not following

Homework Statement A baseball has a terminal speed of 42 m/s in air (ρ = 1.2 kg/m^3). What would be its terminal speed in water (ρ = 1.0 x 10^3 kg/m^3)? A) 0.05 m/s B) 1.5 m/s C) 18 m/s D) 42 m/s E) 1200 m/s Homework Equations D=½Cρ*Av^2 where the magnitude of the drag force (D), relative...

Oh i see, i was actually just using the kinetic energy formula but i didn't properly realize that ƒk was the force of kinetic energy. Thanks for the help

Homework Statement The speed of a 4.0-N hockey puck, sliding across a level ice surface, decreases at the rate of 0.61 m/s2. The coefficient of kinetic friction between the puck and ice is: A) 0.062 B) 0.25 C) 0.41 D) 0.62 E) 1.2 Homework Equations I'm not too sure but i know that : If the...