Recent content by Vac1

The reason I'm trying to factor it is so that I can divide it by x. [FONT=Times New Roman] $$\large\frac{x}{(x^{\frac{1}{n}}+a)^{n-1}}$$ [FONT=Times New Roman] I'm not concerned with the remainder at all but I'm looking for a result that should be equal to: $$\large x^{\frac{1}{n}}-((n-1)a)$$...

I am trying to factor the following equation $$\large(x^{\frac{1}{n}}+a)^{n-1}$$ but the fact that the exponent is n-1 is throwing me off. How could I go about factoring out this equation? Thanks.