Recent content by Valerion

Thank you for your help!

Ok, I think I got it. a_1 = (2*(µ_k*m_1*g*cos(theta) + m_1*g*sin(theta))-m_2*g ) / (-m_2/2 - 2*m_1)

So the acceleration of block 1 has a negative sign and the acceleration of block 2 has a positive sign. Then, -T + µ_k m_1 gcos(theta) + m_1 gsin(theta) = m_1 a_x1 should be -T + µ_k m_1 gcos(theta) + m_1 gsin(theta) = - m_1*a_x1 ?

Homework Statement A block of mass m1 is at rest on an inclined plane that makes an angle (theta) with the horizontal. The coefficient of static friction between the block and the inclined planed is µs. A massless, inextensible string is attached to one end of the block, passes over a fixed...