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What Happens to Work Done by Gravity in First Law of Thermodynamics?
I began applying first law of thermodynamics (delQ=dE+delW) to a freely falling body. We see that for this case delQ=0, so dE=-delW. As dE consists of both potential and kinetic energies we see that neglecting any viscous losses, dE=0. (At max. height, KE=0,PE=mgh and at bottom most point...- vasudevan349
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- First law Law Thermodynamics
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- Forum: Mechanical Engineering