Recent content by VectorA

I tried and still having some troubles. :(

Ok i will try to solve it now. I hope i get the right answer

Homework Statement Homework EquationsThe Attempt at a Solution First i Found the external forces. Ax =0 , Ay = 8Kn, Jy=8Kn and P = -16Kn Then i took moment about point G to eliminate FH and EG and so was able to find CH = 14.66Kn. I am kind of stuck on how to tackle the problem further...

Is it true that i cannot calculate the magnitude of the vector? because L is a unknown quantity.

(8k +6i) X (L-6i +6j -8k) ----> i replaced L-6 with x So the cross product that i got is = 8x+48(j) - 48(i) +36(k)

(8k +6i) X (L-6i +6j -8k) ----> i replaced L-6 with x So the cross product that i got is = 8x+48(j) - 48(i) +36(k)

Yes, sorry for that mistake. It makes sense now. Just wanted to say I have huge respect for you guys, taking out time, trying to help others in their course work. Thank you very much.

And also the friction force is acting towards right?

I see, so the acceleration is going towards right. Am i right?

It doesn't say anything about the mass directly but since w=mg and we know the weight, we can find the mass.

Can you please just quickly tell me what the next step should be? It would be really appreciated.

yes I guess then it is AD-AC L-6(i) +6(j) -8(k)

is my answer correct?

AC - AD 6-L (i) + 8(k) - 6(j)

I am so sorry for asking stupid questions but does the difference look like this? 6-L(i) + 6(j) + 8(k)