Recent content by Verrine

I think I got it. If I do mv^2/2 -mv0^2/2=Fr*d/2, then mv^2/2 =mv0^2/4. So v=v0 /rad 2 =v0*rad2 /2 =141m/s :):) Thank you . :D

Yes, I know about Kinetic energy and work.

I simply tried to solve the equations with what formulas I knew... I actually have no idea what is going on here. The problem is confusing and I don't really see the connection between the velocity of the bullet and the thickness of the block. Sorry. If you could explain it step by step, I would...

Yes! This is the answer! Can you please explain how you did it? :D

The book is not in English. I had to translate it. But trust me, this is what it says.

It goes through the second block in a separate experiment. To be sincere, I don't know myself what D actually stands for. What they say is that the bullet passes through the first block and it covers a certain distance, which is D. I also saw the D as the thickness of the block, but I am not...

Ok sure. I have an attempt, the problem is that my answer doesn't coincide with the answer in the textbook. For the first block I used the fact that the variation of kinetic energy is equal with the work force, so: 0-m*V0^2/2 =Fr *d => Fr=m*V0^2/2d For the second block: mV^2/2 - mV0^2/2= Fr *...

Homework Statement A bullet goes through a block and covers a distance D with a velocity of V0=200m/s. Calculate the velocity that the same bullet has AFTER passing through another block of the same material but which has half the width of the initial block. Homework EquationsThe Attempt at a...