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Finding two possibilities of depth when volume is given?
OMG unbelievable. Firstly, I didn't think about setting it equal to 2000 and then moving the 2000 over to make it equal to 0. Secondly, What was also messing me up was that I wasn't sure if looking for roots was the way to solve this, not realizing that was the way to solve it and that I had...- VLP1
- Post #6
- Forum: Precalculus Mathematics Homework Help
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Finding two possibilities of depth when volume is given?
Another thing to note is this problem is at the end of a Chapter dealing with: The Rational Zero theorem The Fundamental Theorem of Algebra The Linear Factorization Theorem Descartes Rule- VLP1
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Finding two possibilities of depth when volume is given?
The only thing I left out is the beginning format of the V(x) which was: (x)(x+10)(40-(x+x+10)) The x being depth The x + 10 being length The (40 - (x+x+10)) being width(40) minus (depth + length) OK I compact the problem into the below: -2x3+30x2-20x2+300x Now I need a constant to try the...- VLP1
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Finding two possibilities of depth when volume is given?
Homework Statement Problem - If the volume of the carry-on luggage is 2000 cubic inches, determine two possibilities for its depth. Where necessary, round to the nearest tenth of an inch Homework Equations V(x) = x(x+10)(30-2x) Volume function is given above The Attempt at a Solution I...- VLP1
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- Depth Volume
- Replies: 7
- Forum: Precalculus Mathematics Homework Help