Recent content by vpa021

Thank you ojs. my professor never gave us this formula. Hence, i have a problem with this question and similar questions as this.

What formula is that?

I surely don't understand how to break the distance into 3 parts. Unless of course to divide: 144/3 = 48 m?

this is what i did ΔX = v_0t+.5at^2 Given the total Traveled ΔX= 144m v_0=0 t=4s My equation looks something like this 144m=0+(4s)+.5a(4s)^2 144m=8s^2a a=18m/s^2 but i think this is wrong because i took the total (144m) traveled. I don't know how to get the acceleration at 0m...

You accelerate at a m/s2 for 4.0 s, then coast for 8.0 seconds, then decelerate to a standstill in 4.0 s. In total, you travel 144 meters. What was your initial acceleration? Please show your work as i need to learn from you.

Yes... lol i figured it out :). You can be sure you will be seeing me very often on this forum.

thank you sefrez.

OK. I will try to work this out the way you told me to.

So basically, I should just brake the question up into 3 steps?

What are V-T diagrams?

How far do you travel if, starting from rest, you accelerate at 1.5 m/s2 for 4.0 s, then coast for 8.0 seconds, then decelerate to a standstill in 4.0 s? I am totally confused about the fact you accelerate and then coast, and then slow down. We have 3-t's in this problem and don't know what...