Because this is due to my frame of reference, and taking account into the gravitational acceleration on Earth. I believed the distance traveled that I calculated has no wrong.
Sorry about that. The question asked for
(a) What is the tension in the part of the cable attached to the elevator cage? What is the tension in the part of the cable attached to the counterweight?
(b) The acceleration lasts exactly 1.0 s. How much work has the electric motor done in this...
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For the part (a), set the tension of the string that pulls the elevator be ##T_1## and the tension that pushes the counterweight be ##T_2##. Then we have the following equations:
$$T_1−1200g=1200 \cdot 1.5$$
$$1000g−T_2=1000 \cdot (−1.5)$$
where...