Recent content by woaini

Alright makes sense now.

22220000m/s is the new speed I get?

Oh I see, the formula should be f=v/2L

The dsin remain constant right?

So how do I determine the formula for something closed on both ends?

I guess frequency then. Why would I need to workout the two frequencies first? Wouldn't finding the difference and converting be faster?

So if it's near the 4th order, I would do this: arcsin((4*750)/(42*730)) = 5.61 L*tan(5.61)=0.224m y2=0.224m I'm lost here. :(

Homework Statement A double slit apparatus is illuminated 730 and 558 nm wavelengths. They form a two-colored interference pattern on a measuring screen located at a distance of 2.28 m from the slits. The slit separation is 42 wavelengths of 730 nm light. (a) What order (m) intensity maximum...

Homework Statement A spectroscopist has a spectrometer equipped with a grating with 600 grooves/mm. This grating puts a 1228 nm wavelength range on a spectroscopic plate (a CCD) in order m = 5. The spectroscopist now changes the spectroscopic plate CCD by one that is larger by a factor of 3...

It says the fundamental frequency for a closed cylinder is f=v/4L Therefore the speed I determine using the formula is... v= f*4L = 2.2E7 * 4 *0.505 = 444400000 m/s And the ratio of it to the speed of light is: 444400000 m/s / 3E8 m/s = 0.148 Does this look correct?

So am I suppose to find the beat frequency of the two waves then determine the time? E.g. 850-780=70RPM T=1/f = 0.014s Or do I have to convert the RPM to Hz and then find time? 70RPM=1.167Hz T=0.856898s

Is there an equation to combine the two frequencies?

Does that mean n=1?

How do I know how any nodes and antinodes to draw?

What do you mean yes... What method would I use to find the peak between successive times?