Recent content by wonderswan

Hello MindZiper, This post was made months ago so I thank you for reminding me of it. I think I can provide the correct answer - in fact I've noticed some mistakes I made previously so to clarify I will write it step by step. Firstly something important: We must find the magnitude of the...

Okay here's the next step. \frac{kQ^2}{l^2}\left[\frac{-l\hat{i}-l\hat{j}-l\hat{k}}{l}\right] +\frac{kQ^2}{2l^2}\left[\frac{-2l\hat{i}-2l\hat{j}-2l\hat{k}}{\sqrt{2}l}\right] +\frac{kQ^2}{3l^2}\left[\frac{-l\hat{i}-l\hat{j}-l\hat{k}}{\sqrt{3}l}\right] I don't know how to add them to...

Is this the sum of the individual force components (the vectors are in brackets)? \frac{kQ^2}{l^2}\left[\frac{-l\hat{i}}{l}\right]+\frac{kQ^2}{l^2}\left[\frac{-l\hat{j}}{l}\right]+\frac{kQ^2}{l^2}\left[\frac{-l\hat{k}}{l}\right]...

I have also put the charges along the axis as you have described. So the vector caused by each charge: (1,0,0) \ \ a_1 = -l\hat{i} (0,1,0) \ \ a_2 = -l\hat{j} (0,0,1) \ \ a_3 = -l\hat{k} (1,1,0) \ \ a_4 = -l\hat{i}-l\hat{j} (0,1,1) \ \ a_5 = -l\hat{j}-l\hat{k} (1,0,1) \ \ a_6 =...

Hi, thanks for your response. I'm not sure where I can get the 3.69 value. The resultant vector is 4l\hat{i}+4l\hat{j}+4l\hat{k}. F = \frac{Q^2}{4\pi\epsilon_0R^2}\cdot\hat{a} Is R the magnitude of the resultant vector - it would be \sqrt{48l^2}? I think I'm getting confused.

Hello, I'm having a little trouble with this: Coulomb Force Point Charges on Cube Homework Statement Identical charges of Q (C) are located at the eight corners of a cube with side L (m). Show that the coulomb force on each charge has magnitude: 3.29Q^2/4\pi\epsilon_0l^2 Homework Equations...