Recent content by xasuma

I know that. In my previous post I attempted to combine the 3 of them (normal force, the 'y' component of the external force, and mg). I understand you are trying to make me figure it out on my own but this is a bit frustrating. Thank you all for your help but I'll call this one off.

then: vertical component + normal force = mg? mgsin71.79 + n = 88.2N n = 4.42N

Ok so I am thinking I use Pythagorean theorem to combine them therefore: sqrt(((mgcos71.79)^2)+((mgsin71.79)^2)) = 88.20 N I just realized that is the same as mg. I am confused on this one, to me it makes sense that the normal force = mg, since there is no vertical movement. But I feel...

I see, so I got: 1/2mv^2 = mgh , solve for v (speed) v^2 = 2gh v^2 = 2*9.8*0.1 v= 1.4 m/s --------------------- Now for B. The speed of the pendulum 1 cm above the lowest point. I just changed 'h' from 0.1 to 0.09, did the same calculation as above and got: v= 1.33 m/s Did I do it right...

Ok so for a this is it then: a)http://puu.sh/chQHU/7023dd03b8.png note: on the post above did you mean 'b' and 'c' , instead of 'a' and 'b' respectively? . if so: b)θ = 71.79` and c) would normal force = mg , since there is no movement in the vertical axis? if so: 9.0kg*9.8m/s = 88.2 N ?

This is my understanding of it. Potential energy is stored energy which has the potential to be released. Kinetic energy is the energy an object has while in motion. And energy conservation means that energy can change from potential to kinetic (or others) , since it can't be destroyed nor...

Homework Statement A woman at an airport is dragging her 9.0 kg suitcase at a constant speed by pulling a strapa at an angle of θ above the horizontal. She pulls the streap with a 24.0 N force, and the friction force on the suitcase is 7.5 N. a)Draw a free body diagram of the suitcase b)What...

Homework Statement The pendulum shown (http://puu.sh/chwMZ/90f4b96fb1.png ) swings freely, turning around at a height of 10 cm above the lowest point in its swing. It has an unknown mass, but air resistance can be ignored. a) Use energy conservation to find its speed at the lowest point of...