Recent content by yojayydee

so Vf^2=Vy^2+2ad which vf = 0

how long it takese to get half way up... so would you double time once yuh find it ?

do d = vy*t +.5at^2 and d = 25 and i know vy and a ?

that would be the answer for part a .? then for b i use v to find vx then but i don't know either d or t for d=vx * t

so you can do Vf^2= Vi^2 +2ad which vf=0 d=25 a= -9.81 this gives you vy and then you can find v ?

but how can i find Vy if i don't know V and just the degrees

A cannon located 60m from the base of a vertical 25 m cliff shoots a shell at 43 degrees above the horizontal. What is the minimum muzzle velocity be for the shell to clear the top of the cliff ? The ground at the top of the cliff is level, with constant elevation of 25 m above the cannon, How...

okaii i got c for b thought you will use the equation vf^2 = vi^2 +2ad vi = 0 d = (answer to a) + 15m a = +9.81 m/s^2 solve for vf and that's the answer is that correct.?

for the second problem i found maximum height: vf^2=vi^2+2ad which: vi=vy=16.3m/s a= -9.81 m/s^2 d=13.6 m Im stuck on these now The magnitude of the velocity of the rock before it strikes the ground ? The horizontal distance from the base of the building to the point when the rock strikes the...

Homework Statement A cannon located 60m from the base of a vertical 25 m cliff shoots a shell at 43 degrees above the horizontal. What is the minimum muzzle velocity be for the shell to clear the top of the cliff ? The ground at the top of the cliff is level, with constant elevation of 25 m...

A cannon located 60m from the base of a vertical 25 m cliff shoots a shell at 43 degrees above the horizontal. What is the minimum muzzle velocity be for the shell to clear the top of the cliff ? The ground at the top of the cliff is level, with constant elevation of 25 m above the cannon, How...