The forces initially acting on the ring are:
mg DOWN
friction UP
normal RIGHT
spring LEFT
If the ring does not move, that means that Fd = mg.
I already found that the normal force acting on the ring is equal to F * sinϴ, where ϴ is the angle between the pole and the spring.
So, Fd = u*N = u * F...
First, the ring will fall down a bit (a distance I need to find), because the Force of Friction and the Force of the spring x cos@ (where @ is the angle between the pole and the spring) will be bigger than mg.
The ring should later go up, to above its starting point (I think)
I drew the...
Homework Statement
Problem: http://imgur.com/a/Sw2zA
Hi all,
I was given this problem as homework and I have almost no clue on how to solve it. I have tried for some time with no luck.
Homework Equations
We learned about kinetic and potential energy as well as work.
W = F*d
W = delta KE
PE =...