Recent content by Yuval M

The forces initially acting on the ring are: mg DOWN friction UP normal RIGHT spring LEFT If the ring does not move, that means that Fd = mg. I already found that the normal force acting on the ring is equal to F * sinϴ, where ϴ is the angle between the pole and the spring. So, Fd = u*N = u * F...

First, the ring will fall down a bit (a distance I need to find), because the Force of Friction and the Force of the spring x cos@ (where @ is the angle between the pole and the spring) will be bigger than mg. The ring should later go up, to above its starting point (I think) I drew the...

Homework Statement Problem: http://imgur.com/a/Sw2zA Hi all, I was given this problem as homework and I have almost no clue on how to solve it. I have tried for some time with no luck. Homework Equations We learned about kinetic and potential energy as well as work. W = F*d W = delta KE PE =...