Recent content by Zach Smith

Alright, I've read some more, thought it over, and I think I finally get it now. Thanks for all of your help ;p. I feel a bit dense how I kept getting it wrong, but I'm confident with my idea now. Thanks again =) I have no idea how to set the thread title to solved, though. Or do I just edit it...

Carbon 14 also exists, which has 2 more neutrons. The identity of each element is defined by the amount of protons in it, so a carbon atom will always have 6 protons. Carbon-12 is used because Carbon 12 is more abundant compared to its isotopes than other elements.

If you have a number of particles equal to Avogadro's Constant, the mass of said quantity is equal to the relative molecular/formula/atomic mass in grams. 6.023*10^23 Carbon 12 atoms have a mass of 12 grams. 6.023*10^23 Hydrogen atoms have a mass of 1 gram. So if you know the mass of...

I might be looking at this problem the wrong way, or you might want a highly specific answer, forgive me if so. What is the mass of one mole of Carbon 12 atoms? How many particles are there in one mole? If X particles have a mass of Y, what is the mass of one particle?

Ah, sorry for my lack of a reply. Your response only confounds me further. The calculations that I have written down (and thus been given) end up calculating the value of the normal force. Does this mean that they were wrong in calculating this force? Or are they not calculating the normal...

I think I can help here: When the object hits the floor, its energy is changing from kinetic to thermal. Either way, it has the same net energy due to conservation of energy. So we know that the kinetic energy lost is equal to the thermal energy gained. What is the expression for the amount...

I believe I understand the majority of what's going on now, which is great. However, I do have a few issues left over: Firstly, why is it that the passenger can "feel" the normal force acting on them, not the centripetal force? It would make more sense to me that they feel the overall effect...

Okay, some searches here, more browsing of the tubes and an hour of relaxation has lead me to a crudely formed understanding of how my problem works. I'd appreciate if anyone could correct me where I've gone wrong and fill in the gaps. The centripetal force is not a "real" force itself in...

[SOLVED] Centripetal Force and G Forces while traveling over a hill Homework Statement Hi everyone - I've had some problems wrapping my head around the ideas behind centripetal force while traveling over a hill, and, at wits end after journeying for hours through sites which are either...