Recent content by Zarrey

Conservation of energy is different when dealing with electrons it seems. is mass relevent?

why would E be negative?

ok to find the values i have to plug in different numbers into the z value for the equation E = σ/2ε0 E ( 2ε0 ) = σ 1000z ( 2ε0 ) = σ on the range of -10cm < z < +10cm or -.01m < z < .01m

the law of conservation of energy? as it moves closer the PE will decrease and the KE will increase.

i don't have the sigma values to calculate the field though. how am i to find those?

Ok so working on a then. am i wrong in saying that the center will cause no electric potential? the value of r would be 0 which would cause the whole denominator to be 0, which would cause the equation to be undefined. from what i understand the metallic shell is a conductor. and conductors...

The question is asking for numerical values for the charge distribution. i know now what the field will look like but i don't know what I am supposed to be plugging into the equation above. It also asks to fine the electric field, does this mean solve to fine the values at each value of z or...

the proton needs KE in order to move. but what about the charge density? how does that play into KE when it is closer to the center of the ring? that is what i think i am confused about?

would the answer for letter a.) be the center then because if you were to find the potential the r value would be 0 which would cause the answer to be infinite? for b.) would you use Va - Vb? when i go to plug in my equation in my calculator i try to do conversions on the fly. when i find...

The proton needs to increase its KE to a point greater than its PE to move correct? so would i solve for the potential energy of the proton and the ring?

If i were to find the field just outside i would do: Qtotal/(4πε0r2) ?? what would i use for r? my teacher has told us in the past if we were to solve for something that is slightly larger than something else, in this case the gaussian surface, to use +1.0 cm larger than the radius. would it...

the lines would be flowing from the positive source to the negative. so the way to draw the E-field would be to set up the x,y,z coordinate system graph and draw lines that run parallel to the Z axis with arrows pointing downward because the positive is in the upper quadrant and the negative...

wow lol. i can't believe i didnt know that. thank you for reminding me :D

i appreciate the time you are taking to help me by the way.

the equation given for the electric potential. so am i to say that the field only goes along the z axis?