Recent content by zee3b
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Learn How to Sketch a Signal with Step-by-Step Instructions
Thanks <3- zee3b
- Post #8
- Forum: Engineering and Comp Sci Homework Help
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Learn How to Sketch a Signal with Step-by-Step Instructions
hey I was trying to work on it more, is it by any chance something like this- zee3b
- Post #6
- Forum: Engineering and Comp Sci Homework Help
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Learn How to Sketch a Signal with Step-by-Step Instructions
hey so this is my rough sketch of the first and last part how exactly will i fit in the -2u(t-8) in this. I did it in paint lol :( I'm a total noob but in the process of learning more help will be appreciated- zee3b
- Post #5
- Forum: Engineering and Comp Sci Homework Help
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Learn How to Sketch a Signal with Step-by-Step Instructions
Thanks a lot, but I am confused on the 2u part. I can draw u(t-3) and u(t-5) but what is 2u? I'm used to u's- zee3b
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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A little confused in Zero Input response
Any one? :(- zee3b
- Post #2
- Forum: Engineering and Comp Sci Homework Help
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Learn How to Sketch a Signal with Step-by-Step Instructions
Sketch the following signal u(t-3)-2u(t-8)+u(t-5) if it was u(t-3)+u(t-5) I'd be able to sketch it, but the 2u(t-8) is confusing me help me :( I can draw the first part u(t-3) how do I add the second to the graph and then the third- zee3b
- Thread
- Signal
- Replies: 7
- Forum: Engineering and Comp Sci Homework Help
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A little confused in Zero Input response
Guys I know how to solve the simple ones but this one has complex roots I have to find the zero input response (D-1)(D2+1)y(t)=(D2+2)f(t) y(0)=4 y'(0)=3 y''(0)=3 D2= D square. Y' = first derivative Y''= secondI know the roots are +1, j and -j But I don't know how to solve or...- zee3b
- Thread
- Confused Input Response Zero
- Replies: 1
- Forum: Engineering and Comp Sci Homework Help