Wait, I got it. It should just be e^u, so e^(-4*2). /facepalm
Thanks again.
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Thanks for the response. I've managed to arrive at the proper answer, but I don't grasp the logic completely. I start with:
\int_{1}^{2} 2e^{-4x}
I set u=-4x and dx=(-1/4) du, so then:
-...