Recent content by Ziliba

No! Half of the things which are considered to be very important here are not even mentioned in my country! Anyway, thank you very much! I'm happy now:)

I just... Chemistry here is so different than in my country oo)

The experiment above allowed me to determine the ratio between the cooper sulphate and the water by measuring the mass of cooper sulphate before and after heating (We assumed that the mass lost was that of the water lost).

...Yes:nb)

Sorry! I'm not used to writing about such things( We measured the mass of hydrated sulphate, then we measured the mass of dehydrated cooper sulphate. m(H2O)=m(hydrated CuSO4) - m(dehydrated CuSO4) then we converted m(H2O) and m(dehydrated CuSO4) into moles. then we found the ratio n(CuSO4):n(H2O)

Nope. We took hydrated cooper sulphate,measured it, heated it, measured again, calculated the mass of water, turned everything in moles, saw the ratio.

Nope. We took hydrated cooper sulphate,measured it, heated it, measured again, calculated the mass of water, turned everything in moles, saw the ratio.

Hello! I need a little help! At school we did an experiment. We took cooper sulphate (CuSO4.5H2O) and heated it.Then we tried to see whether there are five moles of water to each mole of cooper sulphate. I am asked to "start with a brief statement of how the experiment allowed you to determine...