Recent content by Zinger
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Electrolytes nd freezing point. on mobile, pardon my typing.
im sorry I am in chemistry class nd on my mobile, i did put effort not everyone has time to make things perfect -
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Electrolytes nd freezing point. on mobile, pardon my typing.
in chem. class asked the question nd he ignored me, i hope smeone here can help me? wht are the properties of electrolytes nd how do yu kno they coduct electcity nd also how ud yu determinet lowest freezing eezing poin -
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Permutations with Standard Form Equations: Solving for n
ooh okay thanks :) you helped me a lot, there are some aspects i still don't understand however, but i'll ask my teacher. youre a big help.- Zinger
- Post #8
- Forum: Precalculus Mathematics Homework Help
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Permutations with Standard Form Equations: Solving for n
hmm okay i understand. i tried that and this was my process/answer: i cross mult - n!(n-3)!=8n!(n-4) i then divided (as you suggested) n!(n-3)!/8n! = 8n!(n-4)!/8n! i then tried to isolate the N by adding the 4 onto the other side giving me (n+1)!/8 = n! I tried solving like a normal...- Zinger
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Permutations with Standard Form Equations: Solving for n
yeah, this is the stage I am talking about, exactly what am i suppose to do to simplify. im thinking to cross mult. b/c its a proportion and turn it into a quad form? the problem is, the factorials; how can I simplify with all of them? and there are no factorials for N! (that I can solve out)...- Zinger
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Permutations with Standard Form Equations: Solving for n
Homework Statement the problem states solve for n. nP4 = 8(nP4) Homework Equations no relevant equat. i can think of? The Attempt at a Solution my attempt at this was nP4 = 8(nP3) idk what i tried to do, but i tried to get it in standard form i guess: n!/ (n-4) = 8(n!)/(n-3) it...- Zinger
- Thread
- Form Permutation Standard
- Replies: 7
- Forum: Precalculus Mathematics Homework Help