parallel-plate-capacitor

$$ E = \frac{5.0\;\mathrm{V}}{0.020\;\mathrm{m}} = 250\;\mathrm{V/m} F = q\,E = (-e)\times E = -(1.602\times10^{-19}\;\mathrm{C})\times250\;\mathrm{V/m} = -4.005\times10^{-17}\;\mathrm{N} |F| = 4.005\times10^{-17}\;\mathrm{N} a = \frac{|F|}{m_e} =...