PDA

View Full Version : Conservation of Energy


suspenc3
Dec11-05, 03:48 PM
during a rockslide a 520kg rock slides from rest down a hillside that is 500m long and 300m high. The coeeficient of kinetic friction is 0.25. If the gravitational potential energy U of the rock-earth system is zero at the bottom of the hill, what is the value of U just beofre it slides?

I know this is wrong, but I tried:

U_g = mghcos \Theta
U_g = 9.2 x 10^5J

What do I do?

DaleSpam
Dec11-05, 04:08 PM
This is a good question. There is too much information given in the problem. Specifically, neither the length of the hillside nor the coefficient of friction are important. The gravitational potential energy is just U = mgh. The statement about U = 0 at the bottom of the hill just establishes that h = 0 at the bottom of the hill (since m and g are never 0).

The important part is: do you understand why the friction and length are unimportant in this question?

-Dale

suspenc3
Dec11-05, 04:22 PM
well friction wouldnt matter because it only has to do with thermal energy?

but there are more parts to the question, that is why alot of the info seems useless.

Why doesnt the angle come into play when calculating potential energy?

naeblis
Dec11-05, 05:46 PM
well friction wouldnt matter because it only has to do with thermal energy?
but there are more parts to the question, that is why alot of the info seems useless.
Why doesnt the angle come into play when calculating potential energy?

Potential energy [U] is the energy a mass has at rest, potentially it could fall and turn that energy into kinetic energy. change in U is = change in K [conservation of energy] U doesnt even care about any angles because there is no angle involved with a rock sitting in one place.

DaleSpam
Dec11-05, 06:08 PM
That and also gravity is a conservative field. Meaning that the path you take (the angle) is irrelevant, only the change in the potential is important.

Suspenc3, you hit the key idea about the friction. Basically, if it were frictionless than all of the PE at the top would go into KE at the bottom. With the friction some of the PE will go to heat and some will go to KE, but the initial PE is still the same.

-Dale

gunblaze
Dec11-05, 06:54 PM
Ya..Other information are irrelevent.
You can simply use mgh to find the change in GPE, then add it to zero.. U shld get an answer.