What is the energy of one of the orange light photons?

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SUMMARY

The energy of one orange light photon produced by an Argon gas laser with a wavelength of 6.3E-7 meters and a frequency of 4.76E14 Hz is calculated to be 3.14E-19 joules using the formula E=hf, where h is Planck's constant (6.6E-34). The momentum of the photon is determined to be 1.05E-27 kg·m/s, derived from the relationship p=h/λ. The laser emits approximately 1.66E15 photons per second, calculated by dividing the total power output (5.2 mW) by the energy per photon. The relationship between the number of emitted photons and the frequency of light is confirmed through these calculations.

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Physicists, optical engineers, and students studying quantum mechanics or laser technology will benefit from this discussion, particularly those interested in photon behavior and energy calculations.

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The Argon gas laser produces orange light of wavelength 6.3E-7 meters and of frequency 4.76E14 Hz. The laser output is 5.2 mW
a. What is the energy of one of the orange light photons?
b. What is the momentum of one of the orange light photons?
c. How many photons per second does this laser emit?
d. What is the realtionship between (c) and the frequency of the light
 
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a. the energy of a photon is hf.
b.
from special relativity [tex]E^2=m^2c^4+p^2c^2[/tex]
since the rest mass of a photon is zero, it becomes [tex]E=pc[/tex]
so, [tex]p = \frac{E}{c}[/tex]
since [tex]E = hf = h (\frac{c}{\lambda})[/tex],
[tex]p = (\frac{hc}{\lambda}) *(\frac{1}{c})[/tex]
[tex]p = \frac{h}{\lambda}[/tex]
c. okay, you know the energy per second the laser emmits right?
how many times the energy of a single photon is it?
d. what's the relation between f and c? (hint: you can find it on this post...)
 
Last edited:
a 6.6E-34(4.76E14)
=3.14E-19
b p=6.6E-34/6.3E-7
=1.05E-27
c 5.2E-4/3.14E-19
=1.66E15
d ...i can't see a relation between
1.66E15 photons per second
and 4.76E14 Hz
unless i did something wrong
 

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