proof

[Tony11235]

Prove that a stick of proper length L has a length L' in a frame in which it moves with speed v along a line that makes an angle theta with it's length is given by

L' = L \sqrt{\frac{1-v^2 / c^2}{1 - (v^2 / c^2)\sin^2{\theta}}}

My problem here is the picture I think. So the stick overall is moving with speed v, but the stick is not necessarily parallel to v, but at an angle created by the direction of v and the stick?

[Tom Mattson]

So the stick overall is moving with speed v, but the stick is not necessarily parallel to v, but at an angle created by the direction of v and the stick?


Yes.

You need to remember that your stick is only contracted in the direction of motion. So just for definiteness say that \vec{v}=v\hat{i}. Then the stick is contracted in the x-direction but not in the y-direction.

Once you have the two components in the frame in which the stick has velocity \vec{v} you can find its total length.

[Tony11235]

Got it. I went that direction earlier, but for some reason it didn't look as if the expression I derived was equivalent. BUT after some algebra..........