tandoorichicken
Dec11-03, 09:16 PM
I think Mr. Gishe went trigger happy when he was assigning homework today.
y=\sqrt{a^2-x^2} where -a<=x<=a is a semicircle with r=a
show why \int_{-a}^{a} \sqrt{a^2-x^2}\,dx = \frac{1}{2} \pi a^2
(I think that's how its written)
y=\sqrt{a^2-x^2} where -a<=x<=a is a semicircle with r=a
show why \int_{-a}^{a} \sqrt{a^2-x^2}\,dx = \frac{1}{2} \pi a^2
(I think that's how its written)