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An object of mass m is tied to a light string wound around a wheel that has a moment of inertia I and radius R. The wheel bearing is frictionless and the string does not slip. find the tension and the acceleration of the object.
I think mg-T=ma
and that I=MR^2
thats all i know can someone help me please
thank you
You need to apply Newton's 2nd law to each body: the mass and the wheel.
Originally posted by bard
I think mg-T=ma
Right. That's Newton's 2nd law applied to the mass.
Now apply it to the wheel, using the rotational form: Torque = I*α (you tell me the torque).
To relate the two equations, note that a = R*α.
Hi Doc Al,
Almost solved it
the a i use here will be angular acceleration
so
net torque=T*R or
Ia=T*R
Ia=(mg-mRa)R
Ia=mgr-mR^2a
Ia+mgR^2a=mgr
a(Ia+mR^2)=mgr
a=mgr/I+mR^2
for acceleration the tension is a=mR^2g/(I+mr^2)
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