moham_87
Jan9-04, 07:44 PM
i wish i could find a solution for that poblem
it is about inverse function:
Show that the function has an inverse function, and find [(d/dx)f^-1(x))] x=a for the given number a
f(x)=e^3x + 2e^x - 5 , x>=0 , a=-2
Here i proved that the function has an inverse by finding f'(x), and found that it is increasing at the given interval.
then f(x)= -2 to find "x", and then substitute in the theory:
g(a)=1/[f'(g(a))]
the problem here is that i can't find "x"
where, e^3x + 2e^x - 3 = 0
please i need help, any efforts will be appreciated
it is about inverse function:
Show that the function has an inverse function, and find [(d/dx)f^-1(x))] x=a for the given number a
f(x)=e^3x + 2e^x - 5 , x>=0 , a=-2
Here i proved that the function has an inverse by finding f'(x), and found that it is increasing at the given interval.
then f(x)= -2 to find "x", and then substitute in the theory:
g(a)=1/[f'(g(a))]
the problem here is that i can't find "x"
where, e^3x + 2e^x - 3 = 0
please i need help, any efforts will be appreciated