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teo
Jan11-04, 05:25 AM
hi, first off just have to say these boards kick serious ***!!! Too much interesting posts on here, really like the Mechanical eng board since thats what im doing at uni :)

Right, to the problem,

I do the integral and get the below answer,

Bn = 1/pi [-Cos nt/n] between pi/2 and 0
Bn = 1/pi [[-Cos n(pi/2)/n]-1/n]

but then my notes skip from this to another line,

Bn = 1/npi [1-Cos nt]

The n gets taken out and 1 comes from Cos n0 but why do the signs change?

teo
Jan11-04, 05:33 AM
LOL just looked at it again, and i forgot that there's a minus infront of the cos nt/n which makes

Bn = 1/npi [(-cos nt)-(-1)]

which answers my question :)