View Full Version : find
ashrafmod
Sep17-06, 02:51 AM
1\(5.6)+1\(5.6.7)+1\(5.6.7.8)+..............
arildno
Sep17-06, 09:21 AM
Well, rewrite this as:
\frac{1}{5*6}+\frac{1}{5*6*7}+\frac{1}{5*6*7*8}+++ +=\frac{4!}{6!}+\frac{4!}{7!}+\frac{4!}{8!}+++=4!* (\sum_{n=0}^{\infty}\frac{1}{n!})-4!*(\sum_{n=0}^{5}\frac{1}{n!})
see if you can get somthing out of this.
Hint:
e^x = \sum _{n=0} ^{\infty} \frac{x^n}{n!}
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