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Mesmer
Oct3-06, 05:47 PM
I understand everything in the solution of this problem, except the expresson
2I_{x}I_{2}=16W supplied. can some one please tell me whats going on here?

I thought that Power was the product of current and voltage. How can I get power out of the current source in the center of the mesh?


http://img511.imageshack.us/img511/3175/screenshot003zo4.th.jpg (http://img511.imageshack.us/my.php?image=screenshot003zo4.jpg)
Saketh
Oct3-06, 05:53 PM
I cannot see your document (approval usually takes a while), but I have a question: is the 2 referring to 2 ohms of resistance? Based on your description, it seems like the 2 is 2 ohms of internal battery resistance.

Also, remember that:
V = IR
P = IV
Therefore P = I^2R.
Mesmer
Oct3-06, 05:55 PM
No, sorry there are not resistors in the diagram.
berkeman
Oct3-06, 06:07 PM
I thought that Power was the product of current and voltage. How can I get power out of the current source in the center of the mesh?
Attachment is still pending approval, but you get power from a current source based on the voltage that is across the current source as it supplies the current. If you supply current into a 10V load, that's 10x the power compared to if you source that current into a 1V load.
Mesmer
Oct3-06, 06:23 PM
Can anyone see the image that I have linked to?
Stevedye56
Oct3-06, 06:26 PM
Its approved now.
Mesmer
Oct3-06, 07:34 PM
any suggestins now that you can view the file?
Mindscrape
Oct3-06, 09:59 PM
I understand everything in the solution of this problem, except the expresson
2I_{x}I_{2}=16W supplied. can some one please tell me whats going on here?

I thought that Power was the product of current and voltage. How can I get power out of the current source in the center of the mesh?



Are you doing mesh power(???) analysis?

Anyway, to answer your question, the 2I_x I_2 = 16W is a power because it uses the dependent voltage source, which has a voltage of 2I_x.

Any other questions?
Mesmer
Oct3-06, 11:29 PM
Are you doing mesh power(???) analysis?

Anyway, to answer your question, the 2I_x I_2 = 16W is a power because it uses the dependent voltage source, which has a voltage of 2I_x.

Any other questions?

I see now. Thank you!!