How Is Force Calculated on a Charge at the Center of a Charged Semicircle?

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The discussion centers on calculating the force exerted on a charge located at the center of a semicircle formed by a line of positive charge. The semicircle has a radius of 60.0 cm and a total charge of 12.0 microcoulombs, with charge density described by the equation [lamb] = [lamb]naught cos [the]. The user calculated a force of -0.526 N, while the correct answer is -0.707 N, indicating a discrepancy that requires clarification on the calculation method.

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mateoguapo327
help! I need help with this homework problem.

--A line of positive charge is formed into a semicircle of radius R=60.0 cm. The charge per unit length along the semicircle is described by the expression [lamb]= [lamb]naught cos [the] . The total charge on the semicircle is 12.0 microcoulombs. Calculate the total force on a charge 3.00 microcoulombs at the center of curvature.--

The figure shows the semicircle with is center at the origin going from 0 to pi. [the] is the angle formed by dragging R clockwise from the positive y axis.

the answer in the book is -0.707Nj and I got -0.526N. Can someone please help me figure out how to properly go about solving this problem?
 
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but shouldn't this go in the homework help section? you might get a better response there.
 

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