Parrallel Resistance

[nautica]

A 6 volt battery supplies a total of 48W to two identicle headlights in parrallel. The resistance in each bulb is:

My confusion here is that I am not sure where the watts would fit into resistances.

Could someone lead me in the right directions.

thanks
nautica

[jamesrc]

Use the power to find the current through each lightbulb (P = VI); then use Ohm's law to find resistance.

[nautica]

So

48W=6VI, so 8 total, which would give 4 in each, right?

thanks
nautica