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tgoot84
Feb18-04, 08:30 PM
Alright i don't nessesarily need an answer for this but maybe just a way to set it up. The problem is worded weird and no one can figure it out.

A passenger walks from one side of the ferry to the other side as it approaches a dock. If the passenger's velocity is 1.2 m/s due north relative to the ferry, and 4.5 m/s at an angle of 35 degrees west of north relative to the water, what are the direction and magnitude of the ferry's velocity relative to the water?

(blank) degrees west of north
(blank) m/s

jamesrc
Feb19-04, 12:33 AM
You just have to do some vector addition.

\vec v_{f/w} + \vec v_{m/f} = \vec v_{m/w}

where f = ferry, w = water, and m = man, and / = with respect to.

Drawing the triangle formed by the three vectors may help. Can you take it from there?

gnome
Feb19-04, 12:37 AM
The passenger's velocity relative to the water equals the vector sum (the resultant) of her velocity relative to the ferry plus the ferry's velocity relative to the water.

So
Pw = Pf + Fw

In your problem Fw is the unknown. Set up a diagram illustrating this vector addition & solve it using simple trig.

gnome
Feb19-04, 12:39 AM
How does this keep happening James?[:)]