Calculating Resistance of Aluminum Cylinder

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SUMMARY

The discussion centers on calculating the electrical resistance of a cylindrical aluminum sample given its mass, density, and resistivity values. The formula R = ρL/A is applicable, where R is resistance, ρ is resistivity, L is length, and A is the cross-sectional area. The user can derive the length of the cylinder using the mass and density of aluminum, as well as the relationship between the diameter and height of the cylinder. The shape in question is confirmed to be a solid cylinder, not a hollow tube.

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  • Understanding of basic electrical resistance concepts
  • Familiarity with the formula R = ρL/A
  • Knowledge of density and its calculation
  • Ability to calculate the area of a circle
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Students in physics or engineering, electrical engineers, and anyone involved in material science or electrical resistance calculations.

Roary
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Not an actual problem, but I'm not sure how to figure these out.

I am given the mass of a sample of aluminum. (Let's say it's 112g or something) I am given a shape: cylindrical tube, with the conditions that the diameter of the circular face = the height. (Also given, density of aluminum, a chart with the resistivity values, at standard temp of 20C). How on Earth would I find the resistance between the top and the bottom face of the shape?
 
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R = pl/A (Resistance = resistivity * length/area) is probably the equation to use. But I have no length? The mass given, and density can find the length somehow? (I would use area of a circle only correct?)
 
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Is the shape a "cylindrical tube" or just a cylinder?

Since you haven't given a tube wall thickness I'm assuming you mean a cylinder.

But I have no length?
But you said,
diameter of the circular face = the height
 

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