View Full Version : Hypergeometric Function
Gypsumfantastic
Jan3-07, 07:47 AM
How would i go about showing the special case F(1, b, b; x) of the hypergeometic function is the geometric series and also how the geometric series is = 1/ (1 -x)
Cheers,
Dave
dextercioby
Jan3-07, 08:29 AM
The geometric series ?? I get the series of e^{x} .
Daniel.
Gypsumfantastic
Jan3-07, 08:34 AM
The geometric series ?? I get the series of e^{x} .
Daniel.
I checked it on mathworld that one of the special cases off the hypergeometric function is F(1,1,1;x) is 1 / (1-x) and i want to know how to show it one of my questions is also show that F(1, b, b;x) is the sum to infinity of x^n
dextercioby
Jan3-07, 08:50 AM
Ok, my mistake. The factorial in the denominator simplifies through. So
_{2}F_{1}\left(1,b;b;x\right)=\sum_{\nu=0}^{\infty } x^{\nu}
which converges for |x|<1 to \frac{1}{1-x}
Daniel.
Gypsumfantastic
Jan3-07, 09:04 AM
Ok, my mistake. The factorial in the denominator simplifies through. So
_{2}F_{1}\left(1,b;b;x\right)=\sum_{\nu=0}^{\infty } x^{\nu}
which converges for |x|<1 to \frac{1}{1-x}
Daniel.
Cheers thanks
VatanparvaR
Aug15-08, 06:08 AM
Sorry in advance that I'm posting the same thing in two threads.
I really need it !!!
From Abramowitz's book I got this one
F(a, a+\frac{1}{2}, \frac{3}{2}, z^2)=\frac{1}{2}z^{-1}(1-2a)^{-1}[(1+z)^{1-2a}-(1-z)^{1-2a}]
Now I need to find
F(a, a+\frac{1}{2}, \frac{5}{2}, z^2)
F(a, a+\frac{1}{2}, \frac{7}{2}, z^2)
and, it would be great if I find
F(a, a+\frac{1}{2}, n+ \frac{1}{2}, z^2)
are there any books, handbooks, or websites that I could find this guy?
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