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Caldus
Feb24-04, 12:42 PM
Another question...

If I were given these equations:

x = e^t
y = e^-t

Then I have to find the cartesian product for this parametric curve and then I have to sketch the graph of the curve. So here's the cartesian product I came up with:

Solve for t in y, so:

y = e^-t
ln y = ln e^-t
ln y = -t
t = - ln y

Then plug in to the x part:

x = e^-ln y

Is that part correct?

I have no idea how to graph this...

Help appreciated.

Hurkyl
Feb24-04, 04:20 PM
Do you know any identities applicable to it?

matt grime
Feb24-04, 05:03 PM
Simple method: u^{-r}= 1/u^r
slightly longer metheod, try multiplying x and y together!

or:

-log(p) = log(1/p)
e^log(w)=w

any of those help?