View Full Version : Proving linear transformation
franz32
Feb24-04, 08:54 PM
How will I prove that...
Show that L: V -> W is a linear transformation if and only if
L(au + bv) = aL(u) + bL(v) for any scalars a and b and and any
vectors u and v in V.
For L(au +bv), this is my proof. (Is this wrong?)
L(au + bv) = L [ a(a', b', c') + b(a'', b'', c'')]
= L [ aa' + ba'', ab' + bb'', ac' + bc'' ]
= (aa' + ab' + ac') + ( ba" + bb" +bc")
= a(a' + b' +c') =b(a" + b" + c")
= aL(u) + bL(v)
cookiemonster
Feb24-04, 10:28 PM
I've never studied what you're doing formally, but I've always thought that what you're "proving" is the definition of a linear transformation. Why would you have to prove an arbitrary definition?
cookiemonster
franz32
Feb24-04, 11:22 PM
Yeah that's right. It's an arbitrary definition of the linear transformation. My professor wants me to do it...
In the textbook I'm using, it looks like this
1. L(u+v) = L(u) + L(v)
2. L(ku) = kL(u)
cookiemonster
Feb24-04, 11:37 PM
Well, since it's an arbitrary definition, I don't really see the point of "proving" it.
The only thing I can imagine him doing is asking you to combine the two conditions as it's usually stated. I usually see it in this form:
L[\boldsymbol{v_1}+\boldsymbol{v_2}] = L[\boldsymbol{v_1}]+L[\boldsymbol{v_2}]
L[a\boldsymbol{v}] = aL[\boldsymbol{v}]
My guess is that he wants to see you combine these.
Edit: Just noticed you typed the form yourself. Guess I should read a little more slowly next time...
cookiemonster
I'm with cookiemonster. There is no such thing as proving a definition aside from showing the entry in a dictionary.
Show that L: V -> W is a linear transformation if and only if
L(au + bv) = aL(u) + bL(v) for any scalars a and b and and any
vectors u and v in V.
Well, as has been pointed out,
"L: V -> W is a linear transformation" means
1. L(u+v) = L(u) + L(v)
2. L(ku) = kL(u)
for all vectors u and v in V and scalars k.
The problem is asking you to prove
L: V -> W is a linear transformation
if and only if
L(au + bv) = aL(u) + bL(v) for any scalars a and b and and any
vectors u and v in V.
So, you start with the assumption that "L: V -> W is a linear transformation" then prove "L(au + bv) = aL(u) + bL(v) for any scalars a and b and and any vectors u and v in V."
Then, (as a seperate piece of work!) you start with the assumption "L(au + bv) = aL(u) + bL(v) for any scalars a and b and and any vectors u and v in V." and prove "L: V -> W is a linear transformation".
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