ataglance05
Jan24-07, 06:14 PM
1. The problem statement, all variables and given/known data
1) A pendulum 1 meter in length is pulled back 12.7 degress and the bob has a mass of 1kg. At the moment the bob is released, a)what's the acceleration in m/sec^2 of the bob along the curve of its swing and b)what is the acceleration toward the center of the bob's rotation?
2) For the pendulum in problem 1, how much work was done to pull the pendulum back 12.7 degrees?
2. Relevant equations
i think... to get the acceleration of bob along the curve of its swing...you use:
http://img.photobucket.com/albums/v635/Obstacle01/equationa1.jpg
and
http://img.photobucket.com/albums/v635/Obstacle01/equationa2.jpg
and a^2+b^2=c^2
3. The attempt at a solution
First, i drew the pendulum/free body diagram:
http://img.photobucket.com/albums/v635/Obstacle01/pendulum.jpg
My teacher said to just get a1, which is the acceleration of the bob along the curve of its swing, and a2, the other acceleration.
a)so...
a1=sin(77.3)=opposite/10
.9755=opposite/10
opposite=9.755
9.755^2+b^2=10^2
b^2=4.84
b=2.2
so a1=2.2m/sec^2
b)a2=cos(12.7)=adjacent/10
.9755=adjacent/10
adjacent=9.755
9.755^2+b^2=10^2
b^2=4.84
b=2.2
soa2=2.2m/sec^2
1) i dont think this is right since I get the same accelerations. please help?? Did i do it all right or can you help me solve this problem??
2) All I know is that I need to use the equation PE=mgh and where m is mass, g is gravitational acceleration, and h is the height and height=L((1-cos(theta)). The only thing I really know how to do is get h sine I'm not sure what is L. How do I get that??[/b] HELP ME!!!
THANK YOU!!!
1) A pendulum 1 meter in length is pulled back 12.7 degress and the bob has a mass of 1kg. At the moment the bob is released, a)what's the acceleration in m/sec^2 of the bob along the curve of its swing and b)what is the acceleration toward the center of the bob's rotation?
2) For the pendulum in problem 1, how much work was done to pull the pendulum back 12.7 degrees?
2. Relevant equations
i think... to get the acceleration of bob along the curve of its swing...you use:
http://img.photobucket.com/albums/v635/Obstacle01/equationa1.jpg
and
http://img.photobucket.com/albums/v635/Obstacle01/equationa2.jpg
and a^2+b^2=c^2
3. The attempt at a solution
First, i drew the pendulum/free body diagram:
http://img.photobucket.com/albums/v635/Obstacle01/pendulum.jpg
My teacher said to just get a1, which is the acceleration of the bob along the curve of its swing, and a2, the other acceleration.
a)so...
a1=sin(77.3)=opposite/10
.9755=opposite/10
opposite=9.755
9.755^2+b^2=10^2
b^2=4.84
b=2.2
so a1=2.2m/sec^2
b)a2=cos(12.7)=adjacent/10
.9755=adjacent/10
adjacent=9.755
9.755^2+b^2=10^2
b^2=4.84
b=2.2
soa2=2.2m/sec^2
1) i dont think this is right since I get the same accelerations. please help?? Did i do it all right or can you help me solve this problem??
2) All I know is that I need to use the equation PE=mgh and where m is mass, g is gravitational acceleration, and h is the height and height=L((1-cos(theta)). The only thing I really know how to do is get h sine I'm not sure what is L. How do I get that??[/b] HELP ME!!!
THANK YOU!!!