use a graph to fine a number delta such that

[afcwestwarrior]

/square rootsign 4x+1/ <.5 /X-2/ < delta

2 is x and 3 is y, 3 goes to 3.5 and 2.5, i need help with the absolute value of the square root sign 4x+1

[Gib Z]

Is this what you want?

\sqrt{4x+1} < \frac{x-2}{2} < \delta

[Gib Z]

O wait, last post I assumed the //'s were your grouping symbols. I think theyre absolulote value signs >.<

|\sqrt{4x+1}| < \frac{|x-2|}{2} < \delta

I hope thats what you want.

[HallsofIvy]

This is the second time you have posted this. Thanks to Gib Z for writing out the formula (you forgot the second "|" on the square root). But I still have no idea what "2 is x and 3 is y, 3 goes to 3.5 and 2.5" could mean! 3 doesn't "go" anywhere- it just sits there! And there is no "y" in your expression.

[Gib Z]

To Halls- Look abit closer :p its there.

To OP- I still have no idea what it is you want.

[afcwestwarrior]

i should write it exactly