View Full Version : Intuitively what's the difference between Lie Derivative and Covariant Derivative?
sit.think.solve
Feb5-07, 03:03 PM
Loosely speaking or Intuitively how should one understand the difference between Lie Derivative and Covariant derivative? Definitions for both sounds awfully similar...
There was a recent discussion of the relationship between the Lie and covariant derivatives, which may be useful to you: http://www.physicsforums.com/showthread.php?t=150200.
After reading this, do you ahave any other specific questions?
The covariant derivative uses a connection, while the Lie derivative doesn't.
Doodle Bob
Feb6-07, 04:32 PM
Just to spotlight one of these: The Lie derivative L_X(Y) is basically a dynamical invariant. It measures how compatible the flows of the vector fields are, i.e. how much they commute with each other. If X is generated by the flow \phi_t and Y is generated by \psi_s, then the Lie derivative [X,Y] at point P is the tangent vector at time 0 of the curve given by: t \mapsto \psi_{-t} \circ \phi_{-t} \circ \psi_t \circ \phi_t (P).
Berger describes this as moving P forward in time along the X-curves by t, then moving along the Y-curve by t, then moving backward in time along the X-curve and finally moving backward in time along the Y-curve. If you've ended up back at P, then [X,Y]=0 at P.
In particular, if \phi_s \circ \psi_t=\psi_t \circ \phi_s for all s and t, then [X,Y]=0.
The covariant derivative acts similarly except instead of pushing Y along the X-curves via X's flow, we are pushing Y along X-curve via parallel transport. This explanation, though, is a bit of circular logic, since one usually uses the specific covariant derivative to generate the parallel transport.
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