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stunner5000pt
Feb20-07, 02:07 PM
bb] The dipole transition amplitude for the transition (nlm) -> (n'l'm') is given by [/b]

\int \psi_{n'l'm'}^* \vec{r} \psi_{nlm} d\tau
Is the dipole transition amplitude simply a measure of how likely a certain transiton is??

Heres another question
In converting \psi_{nlm_{l}m_{s}} = C_{n}\psi_{nljm_{j}}
my prof said that finding the Cn would involve a rather messy calculation involving group theory... how does that come about?? How does a simple relation like j = l + s bring about something like that??

thanks for your input!

dextercioby
Feb21-07, 01:07 AM
bb] The dipole transition amplitude for the transition (nlm) -> (n'l'm') is given by [/b]

\int \psi_{n'l'm'}^* \vec{r} \psi_{nlm} d\tau
Is the dipole transition amplitude simply a measure of how likely a certain transiton is??

It's a probability amplitude. Its square modulus gives the transition probability.


Heres another question
In converting \psi_{nlm_{l}m_{s}} = C_{n}\psi_{nljm_{j}}
my prof said that finding the Cn would involve a rather messy calculation involving group theory... how does that come about?? How does a simple relation like j = l + s bring about something like that??



The Clebsch-Gordan coefficients that you need are a result of group theory. Angular momentum theory (including the addition of angular momenta) is a result of group theory.