View Full Version : Springs in series and parallel : Problem for U
sss_1981
Apr21-07, 07:12 AM
I came across an objective question on the topic 'Springs in series and parallel' .. Have i asnwered it correctly?
Q. A Force of 5Kg compresses 2 springs in series by 10 cm. What will be the compression when the same force acts on the same 2 springs but when the springs are in parallel?
Choices >>
1) 5 cm
2) 10 cm
3) 2.5 cm
4) 20 cm
MY ANSWER >> 2.5 cm
Please correct me if I am wrong..
pcdagr8
Apr21-07, 09:31 AM
You are correct !
though it should have been mentioned that the springs are identical but as nothing is mentioned we can take them to be identical
sss_1981
Apr21-07, 11:54 PM
Thanks buddy...
Oh yes, U r spot on.. I forgot to mention that the springs are identical..
The logic I followed was >>
In series,
* The compression is 10 cm
* This means each spring compresses by 5cm
* Since the springs are in series, both the springs experience the full 5 kg
force
* So, each spring compresses 1 cm for 1 kg (Spring constant=1)
In parallel,
* Now, the force is divided between the 2 springs
* So, force acting on each spring is 2.5 N
* So, in this case, the spring compresses to 2.5xSpring constant(1) = 2.5 cm
Hope I am right with my logic too.. Sorry, I should have mentioned this earlier:biggrin:
pcdagr8
Apr22-07, 09:53 AM
most welcome
well....your logic seems correct but some problem in units.
u say spring constant is 1??
if its 1 it must be 1 cm/kg wt but in si it will be not be so
but later you say the force on each spring is 2.5 N it can't be its 2.5kg wt
otherwise your soln is correct
n btw ...
if you are preparing for some objective type examinatiom
then you can use
for series
1/k=1/k1+1/k2
and parallel
k=k1+k2
where k is equivalent spring constant
sss_1981
Apr23-07, 12:12 AM
Thanx chap..:approve:
(Ooops, the 2nd force that I mentioned is 2.5 KG (Not Newton) ... by mistake I wrote it as 2.5N)
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